1.

The pressure exerted by 12 g of ideal gas at temperature t°C in a vessel of volume V litre in one atmosphere. When the temperature is increased by 10°, the pressure increases by 10%. If molecular mass of the gas is 120, calculate the temperature t' and volume V.

Answer»

Moles of gas 12/120 = 0.1

pV = nRT

or, 1 x V = 0.1 x R x (273 + t)    ...(i)

After temperature change p = 1 + 10/100 = 1.1 atm

T = (t + 273 + 10)

= (283 + t) K

∴ 1.1 x V = 0.1 x R x (283 + t)    ...(ii)

Divide (ii) by (i), we have

1.1/1 = {283 + t}/{273 + t}

or, t = -173°C

Substituting the value of t in equation (i)

1 x V = 0.1 x 0.082 x (273 - 173)

or, V = 0.82 L



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