Saved Bookmarks
| 1. |
The pressure exerted by 12 g of ideal gas at temperature t°C in a vessel of volume V litre in one atmosphere. When the temperature is increased by 10°, the pressure increases by 10%. If molecular mass of the gas is 120, calculate the temperature t' and volume V. |
|
Answer» Moles of gas 12/120 = 0.1 pV = nRT or, 1 x V = 0.1 x R x (273 + t) ...(i) After temperature change p = 1 + 10/100 = 1.1 atm T = (t + 273 + 10) = (283 + t) K ∴ 1.1 x V = 0.1 x R x (283 + t) ...(ii) Divide (ii) by (i), we have 1.1/1 = {283 + t}/{273 + t} or, t = -173°C Substituting the value of t in equation (i) 1 x V = 0.1 x 0.082 x (273 - 173) or, V = 0.82 L |
|