Saved Bookmarks
| 1. |
The present population of a city is 180000. If it increases at the rate of 10% per annum, then find its population after 2 years. |
|
Answer» Present population of city = 180000Rate of increase per annum(per year) = 8℅ Hence,Population after 1 year = 180000 + 8℅ of 180000 = 180000+8/100*180000 = 180000+14400 = 194400 Now, Population after 2 years = 194400+8/100*194400 = 194400+15552 = 209952 Hence, Population of city after 2 year = 209952 P=1,80,000R=10%n=2 years A=P(1+R|100)^nA=1,80,000(1+10|100)^2A=1,80,000(1+1|10)^2A=1,80,000(10+1|10)^2A=1,80,000(11|10)^2A=1,80,000×11|10×11|10A=1800×11×11A=2,17,800Therefore,the population after 2 years is 2,17,800. |
|