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The potential energy of a projectile at maximum height is 3/4 times kinetic energy of projection. Its angle of projection is1) 30°2) 45°3) 60° 4) none |
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Answer» Potential energy at the highest POINT = mgh Kinetic energy at the highest point = 1/2 mv² Now, as per question..... P.E. = (3/4) K.E. mgh = (3/4) mv²/2 [HEIGHT of PROJECTILE = v²sin²Ø/2g] g(v²sin²Ø)/2g = (3/8)v² sin²Ø/2 = 3/8 sin²Ø = 3/4 sinØ = √3/2 sinØ = sin 60° Ø = 60° Henceforth, The angle of Projection of particle = Ø = 60° |
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