the potential energy of a particle of mass 1 kg moving along x axis is given by U(x) = (x^2/2 - x) J if the total mechanical energy of particle is 2 J then find its maximum speed

the potential energy of a particle of mass 1 kg moving along x axis is

1.	the potential energy of a particle of mass 1 kg moving along x axis is given by U(x) = (x^2/2 - x) J if the total mechanical energy of particle is 2 J then find its maximum speed
Answer» 2Speed will be max when kinetic energy is MAXIMUM so potential energy will be MINIMUM so differentiating the function put it equal to 0 so we obtain minimum for x=0 now kin potential energy is 0 and kinetic energy will be 2 .mv^2/2 is equal to 2 m is 1 kg therefore v=2 .

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the potential energy of a particle of mass 1 kg moving along x axis is given by U(x) = (x^2/2 - x) J if the total mechanical energy of particle is 2 J then find its maximum speed

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