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The potential energy of a particle is determined by the expression `U=alpha(x^2+y^2)`, where `alpha` is a positive constant. The particle begins to move from a point with coordinates `(3, 3)`, only under the action of potential field force. Then its kinetic energy T at the instant when the particle is at a point with the coordinates `(1,1)` isA. `8 alpha`B. `24 alpha`C. `1 b alpha`D. zero |
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Answer» Correct Answer - C M.E. = U + K = constant `U_(i) + K_(i) = U_(f) + K_(f)` `alpha (3^(2) + 3^(2)) + 0 = alpha (1^(2) + 1^(2)) + K_(f)` |
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