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The potential energy of a harmonic oscillator of mass 2 kg in its mean position is 5 J. If its total energy is 9J and its amplitude is 0.01 m, find its time period. |
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Answer» SOLUTION :`1/2kA^(2)+(9-5)=4J` `:.k=8/(A^(2))=8/((0.01)^(2))=8xx10^(4)N//m` `T=2pisqrt(m/k)=2pisqrt(2/(8xx10^(4)))=(PI)/100S` |
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