1.

The potential energy of a harmonic oscillator of mass 2 kg in its mean position is 5 J. If its total energy is 9J and its amplitude is 0.01 m, find its time period.

Answer»

SOLUTION :`1/2kA^(2)+(9-5)=4J`
`:.k=8/(A^(2))=8/((0.01)^(2))=8xx10^(4)N//m`
`T=2pisqrt(m/k)=2pisqrt(2/(8xx10^(4)))=(PI)/100S`


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