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The potential energy of a force filed `vec(F)` is given by `U(x,y)=sin(x+y)`. The force acting on the particle of mass m at `(0,(pi)/4)` isA. 1B. `sqrt2`C. `(1)/(sqrt2)`D. 0 |
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Answer» Correct Answer - A `vec(F) = DeltaU = - cos (x + y) hat(i) - cos (x + y) hat(j)` `vec(F) |_(((0, pi //4))) = 1` |
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