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The potential energy (in SI units) of a particle of mass `2kg` in a conservative field is `U=6x-8y`. If the initial velocity of the particle is `vecu=-1.5hati+2hatj`, then find the total distance travelled by the particle in the first two seconds.A. `10m`B. `12m`C. `15m`D. `18m` |
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Answer» Correct Answer - C `vec(v)=-(delU)/(delx)hat(i)-(delU)/(dely)hat(j)=-[6hat(i)]+[8]hat(j)` `=-6hat(i)+8hat(j)` `:. vec(a)=-3hat(i)+4hat(j)` has same direction as that of `vec(u)=(-3hat(i)+4hat(j))/(2)=((vec(a))/(2))` `|vec(a)|=5` `|vec(u)|=5//2` Since `vec(u)` and `vec(a)` are in same direction, particl will move along a straight line `:. S=(5)/(2)xx2+(1)/(2)xx5xx2^(2)` `=5+10=15m. 15m. Ans` |
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