The potential energy function for a particle executing linear SHM is given by V(x) =1/2kx^(2) wher e k is the force constant of the oscillator (figure). For k = 0.5 N/m ,the graph ofV(x) versus x is shown in the figure . A particle oftotal energyE turnsbackwhen it reachesx = pm x_(m) . If V and K indicate the PE and KE , respectivelyof the particle at x = +x_(m) , then which of the following is correct ?

The potential energy function for a particle executing linear SHM is g

1.	The potential energy function for a particle executing linear SHM is given by V(x) =1/2kx^(2) wher e k is the force constant of the oscillator (figure). For k = 0.5 N/m ,the graph ofV(x) versus x is shown in the figure . A particle oftotal energyE turnsbackwhen it reachesx = pm x_(m) . If V and K indicate the PE and KE , respectivelyof the particle at x = +x_(m) , then which of the following is correct ?
Answer» V =0 ,K=E V = E,K=0 `V lt E , K = 0 ` `V = 0 ,K=0` SOLUTION :Total ENERGY is E = PE +KE …(i) At `X = x_(m), v = 0 ,KE = 0 ` From Eqn.(i) `E = pE +0 = PE =V(x_(m)) =1/2 kx_(m)^(2)`