The potential due to a point charge at a distance of 0.3 m is 10^3 V. What will be the electric field intensitydue to the same charge at a distance of 0.4 m?Ans. 1875 V-m

The potential due to a point charge at a distance of 0.3 m is 10^3 V

1.	The potential due to a point charge at a distance of 0.3 m is 10^3 V. What will be the electric field intensitydue to the same charge at a distance of 0.4 m?Ans. 1875 V-m
Answer» Explanation:kq/r1=VI Here k is constant quality is point CHARGE r1 is DISTANCE from point charge VI is POTENTIAL This IMPLIES that kq=V1r1 Electric field at distance r2. from the point charge quality is E=kq/(r2)^2=V1r1/(r2)^2 =(10)^3×0.3/(0.4)^2 =(300/16)=75/4 =18.75 V/m

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The potential due to a point charge at a distance of 0.3 m is 10^3 V. What will be the electric field intensitydue to the same charge at a distance of 0.4 m?Ans. 1875 V-m​

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The potential due to a point charge at a distance of 0.3 m is 10^3 V. What will be the electric field intensitydue to the same charge at a distance of 0.4 m?Ans. 1875 V-m