1.

The potential difference between the cathode and the target in a coolidge tube is 120 kV. What can be the minimum wavelength (in Å) of the X-rays emitted by this tube ?

Answer»

0.4 `Å`
0.3 `Å`
0.2 `Å`
0.1 `Å`

Solution :`lambda_(min) = (12375)/(V)Å = (12375)/(120 XX 10^(3)) Å = 0.1 Å`


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