The position vector →r of a particle of mass 0.1 kg is given by the equation →r(t)=(103t3 ^i+5t2 ^j) m. At t=1 s, the torque experienced by the particle due to force with respect to the origin is given by

The position vector →r of a particle of mass 0.1 kg is given by the

1.	The position vector →r of a particle of mass 0.1 kg is given by the equation →r(t)=(103t3 ^i+5t2 ^j) m. At t=1 s, the torque experienced by the particle due to force with respect to the origin is given by
Answer» The position vector $\to r$ of a particle of mass $0.1 kg$ is given by the equation $\to r (t) = (\frac{10}{3} t^{3}^i + 5 t^{2}^j) m$ . At $t = 1 s$ , the torque experienced by the particle due to force with respect to the origin is given by

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The position vector →r of a particle of mass 0.1 kg is given by the equation →r(t)=(103t3 ^i+5t2 ^j) m. At t=1 s, the torque experienced by the particle due to force with respect to the origin is given by

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