The position vector of three particles of mass m1=3 kg,m2=4 kg and m3=1 kg are →r1=(2^i+^j+3^k) m, →r2=(^i−3^j+2^k) m and →r3=(3^i−2^j−^k) m respectively. Find the position vector of centre of mass of the system of particles.

The position vector of three particles of mass m1=3 kg,m2=4 kg and m3=

1.	The position vector of three particles of mass m1=3 kg,m2=4 kg and m3=1 kg are →r1=(2^i+^j+3^k) m, →r2=(^i−3^j+2^k) m and →r3=(3^i−2^j−^k) m respectively. Find the position vector of centre of mass of the system of particles.
Answer» The position vector of three particles of mass $m_{1} = 3 kg, m_{2} = 4 kg$ and $m_{3} = 1 kg$ are $_{1} = (2^i +^j + 3^k) m,_{2} = (^i - 3^j + 2^k) m$ and $_{3} = (3^i - 2^j -^k) m$ respectively. Find the position vector of centre of mass of the system of particles.

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The position vector of three particles of mass m1=3 kg,m2=4 kg and m3=1 kg are →r1=(2^i+^j+3^k) m, →r2=(^i−3^j+2^k) m and →r3=(3^i−2^j−^k) m respectively. Find the position vector of centre of mass of the system of particles.

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