The position vector of a particle is given vecr= 2thati+3t^(2)hatj-5hatk calculate the velocity and speed of the particle at any instant 't'.

The position vector of a particle is given vecr= 2thati+3t^(2)hatj-5ha

1.	The position vector of a particle is given vecr= 2thati+3t^(2)hatj-5hatk calculate the velocity and speed of the particle at any instant 't'.
Answer» SOLUTION :`vecr = 2thati + 3t^2 hatj - 5hatk` Velocity `vecv = (dvecr)/(dt) =(d)/(dt) (2t hati + 3t^2 hatj - 5 hatk)` `vecv = (2hati + 6T hatj) MS^(-1)` Speed `\|vecv\| = sqrt((2)^2 + (6)^2) = sqrt(40) = 2sqrt(10) ms^(-1)`