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The position vector of a particle is given by `vec r = (2t hati+5t^(2)hatj)m` (t is time in sec). Then the angle between initial velocity and initial acceleration isA. zeroB. `45^(@)`C. `90^(@)`D. `180^(@)` |
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Answer» Correct Answer - C The position ………… `(vecV)= (dvecr)/(dt) = 2hati+10t hatj` `veca = 10 hatj` `vecV(t = 0) = 2hati` `veca(t=0)=10hatj` `implies vecV _|_veca(theta = 90^(@))` |
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