1.

The position vector of a particle is given by `vec r = (2t hati+5t^(2)hatj)m` (t is time in sec). Then the angle between initial velocity and initial acceleration isA. zeroB. `45^(@)`C. `90^(@)`D. `180^(@)`

Answer» Correct Answer - C
The position ………… `(vecV)= (dvecr)/(dt) = 2hati+10t hatj`
`veca = 10 hatj`
`vecV(t = 0) = 2hati`
`veca(t=0)=10hatj`
`implies vecV _|_veca(theta = 90^(@))`


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