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the position of an object moving along x-axis is given by x=a+bt^2 where a = 8.5m and b=2.5m s and t is measured in second. If the object starts from t= 0 , you he velocity at t=2 s​

Answer» V= DX/ DTV = d(a+bt^2)/ dtdifferentiation of a is zero.differentiation of bt^2 is 2bt^2-1/ 2-1 = 2btso, V= 2bt V = 2× 2.5 × 2 V = 10m/s


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