1.

The position of a projectile launched from the origin at t=0 is given by →r=(40^i+50^j) m at t=2 s. If the projectile was launched at an angle θ from the horizontal, then θ is (Take g=10 ms−2)

Answer»

The position of a projectile launched from the origin at t=0 is given by r=(40^i+50^j) m at t=2 s. If the projectile was launched at an angle θ from the horizontal, then θ is

(Take g=10 ms2)



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