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The position of a particle is given by equation x = 4t2- 15t +20.Where x is in meter and t is in seconds. Find the position, velocityand acceleration of particle at 4 seconds |
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Answer» X= 4t^2-15t+20 velocity is F'(x)=8t-15 at t=4 v=8×4-15 =17 acceleration is f''(x)=8 at t=4 a=8 |
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