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The position of a particle at any instant is given by x=8t2-3t3, calculate Instantaneous acceleration at t=2.0s urgent |
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Answer» Explanation: s=8t²-3t³ ds/dt= VELOCITY= d(8t²-3t³)/dt velocity= 16t-9t² and ACCELERATION a= d(velocity)/dt
a= d(16t-9t²)/dt a=16-18t therefore at 2.0s a=16-18×2 a= -20ms-² it MEANS that the body is RETARDING with a retardation of 20ms-². please mark me as brainliest I answer so many questions still people never BOTHER to mark the answer as brainliest please you mark it.. ☺️☺️ |
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