The position coordinates of a particle moving in x-y plane changes fro

1.	The position coordinates of a particle moving in x-y plane changes from (1 m, 1 m) to (3 m, –5 m). Its displacement vector is represented as
Answer» $\underline{\textsf{Given:}}$ $\textsf{Points are (m,m) and (3m,-5m)}$ $\underline{\textsf{To find:}}$ $\textsf{The displacement vector}$ $\underline{\textsf{Solution:}}$ $\textsf{Let the given points be A(m,m) and B(3m,-5m)}$ $\textsf{Then,}$ $\mathsf{\overrightarrow{OA}=m\overrightarrow{i}+m\overrightarrow{j}}$ $\mathsf{\overrightarrow{OB}=3m\overrightarrow{i}-5m\overrightarrow{j}}$ $\textsf{Now,}$ $\textsf{Displacement vector}$ $\mathsf{\overrightarrow{AB}=\overrightarrow{OB}-\overrightarrow{OA}}$ $\mathsf{\overrightarrow{AB}=(3m\overrightarrow{i}-5m\overrightarrow{j})-(m\overrightarrow{i}+m\overrightarrow{j})}$ $\mathsf{\overrightarrow{AB}=2m\overrightarrow{i}-6m\overrightarrow{j}}$ $\underline{\textsf{Answer:}}$ $\textsf{Displacement vector is}$ $\mathsf{2m\overrightarrow{i}-6m\overrightarrow{j}}$