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The population of a city increases 10% every year. In 2019, if the populationis 1,33, 100, what was the population of the city in 2017? |
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Answer» Answer: The population of the city in 2017 was 1,10,000. Step-by-step explanation: This is really easy sum. You just have to apply theformula of increase or decrease. Here's how it should be done :Time (t) = (2019 – 2017) = 2 years Present Population (A) = 1,33,100 Rate of increase of population (R) = 10% LET, the population in 2017 be P. A = P ( 1 + r/100)^t[Tip: I'm applying the formula with the plus because the population is INCREASING. If it's decreasing, use minus] → 133100 = P ( 1 + 10/100)^2 → 133100 = P ( 1 + 1/10)^2 → 133100 = P ( 11/10)^2 → 133100 × 100/121 = P → 110000 = P [Do the calculation yourself, lol :P] I hope this HELPS. I actually learnt this last year and my memory is KINDA hazy about this stuff. But I hope this helps ☺️. |
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