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The polynomials ax3 3x2 + 4 and 2x3 5x + a when divided by ( x 2 ) leave the remainder p and q' respectively. If p 2 q = 4, find the value of a' |
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Answer» x=2 a{2}3-3{2}2+4=8a-8 _p 2{2]3-5{2}+a =6+a _q 8a-8-2(6+a) =4 8a--8-12-2a=4 8a-20-2a=4 8a-2a=4+20 6a=24 a=24/6 a=4 |
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