Saved Bookmarks
| 1. |
The polynomials ax3 + 3x2 − 13 and 2x3 − 5x + a are divided by x + 2. If the remainder in each case is the same, find the value of a. |
|
Answer» Answer: VALUE of a is 5/9 Step-by-step explanation: given divisor is x+2 substituting x=-2 in both polynomials will give the remainder in each case(by remainder theorem) remainder in 1ST case: a (-2)^3+3(-2)^2-13 =-8a+12-13 =-8a-1.....(i) remainder in 2ND case : 2(-2)^3-5(-2)+a =-16+10+a =-6+a.....(ii) from i and ii, we GET: -8a-1=-6+a => -9a=-5 a= 5/9 |
|