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The pole strength of a bar magnet is 48 ampere-metre and the distance between its poles is 25 cm. The moment of the couple by which it can be placed at an angle of 30o with the uniform magnetic intensity of flux density 0.15 Newton /ampere-metre will beA) 12 Newton x metre B) 18 Newton x metre C) 0.9 Newton x metre D) None of the above |
Answer» The torque will be τ = 0.9 N-mOption (C) is correct.Explanation: We are given that: τ = mBsinθ ---- (1) M = m x L M = 48 x 25 x 10^-2 τ = 48 x 25 x 10^-2 x 0.15 τ = 0.9 N-m Thus the torque will be τ = 0.9 N-m Also learn more A 40 kg boy SITS 1.2 m from the fulcrum of a see-saw. Where should another boy of 30 kg sit on the other side in order to balance it? |
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