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The points of intersection of the line `4x-3y-10=0`and the circle `x^2+y^2-2x+4y-20=0`are ________ and ________ |
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Answer» Correct Answer - `(-2, - 6) and (4, 2)` For point of intersection, we put `x=(3y+10)/(4)" in " x^(2)+y^(2)-2x+4y-20=0` `rArr ((3y+10)/(4))^(2)+y^(2)-2((3y+10)/(4))+4y-20=0` `rArr 25y^(2)+100y-300=0` `rArr y^(2)+4y-12=0` `rArr (y-2)(y+6)=0` `rArr y = -6 ,2` when y = -6 `rArr` x = -2 when y = 2 `rArr x = 4 `therefore` point intersection are (-2, -6) and (4, 2). |
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