The points A,B & C lie on the same straight line,the distance AB being

1.	The points A,B & C lie on the same straight line,the distance AB being 60m.A particle crosses the point A with velocity 2m/s and moves with uniform accerleration along the straight line.After crossing the points B,it takes 10 sec to reach C with velocity 5m/s.Find the accerleration of the particle.
Answer» in the given question it is given to you velocity of particle at POINT A is 2m/s .distance between AB is 60m . assume velocity of particle at point B is Vb and particle moving with ACCELERATION a. use velocity-position relationship for path AB this will be equation 1 For line BC it is given to you it take 3sec to reach point C and also known velocity at point C apply velocity time relation for path BC. it will be equation 2. from equation one and two you can easily CALCULATE acceleration of particle. Thank you.

The points A,B & C lie on the same straight line,the distance AB being 60m.A particle crosses the point A with velocity 2m/s and moves with uniform accerleration along the straight line.After crossing the points B,it takes 10 sec to reach C with velocity 5m/s.Find the accerleration of the particle.

Answer»

in the given question it is given to you velocity of particle at POINT A is 2m/s .distance between AB is 60m .

assume velocity of particle at point B is Vb and particle moving with ACCELERATION a.

use velocity-position relationship for path AB

this will be equation 1

For line BC it is given to you it take 3sec to reach point C and also known velocity at point C

apply velocity time relation for path BC.

it will be equation 2.

from equation one and two you can easily CALCULATE acceleration of particle.

Thank you.

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