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The points A(0, 0), B(10, 0), C(5, 5√3 ) are the vertices of the triangle ABC. Find AB, BC, AC and prove that the triangle is equilateral. |
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Answer» A(0, 0), B(10, 0), C (5, 5√3) AB = 10 unit BC = \(\sqrt{(10-5)^2+(0-5\sqrt{3})^2}\) = \(\sqrt{25+75}\) = 10 unit AC = \(\sqrt{(10-5)^2+(0-5\sqrt{3})^2}\) = \(\sqrt{25+75}\) = 10 unit AB = BC = AC ∴ ΔABC is equilateral |
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