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The points (-5, 1), (1, p) and (4, -2) are collinear ifthe value of p is(a) 3(b) 2(c) 1(d) -1Answer it with explanation​

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==> D) -1

Explanation :-

REASON: The points are COLLINEAR if AREA of Δ = 0

= \frac{1}{2} [ \: - 5(p + 2) + 1( - 2 - 1) + 4(1 - p)] - 0

⇒- 5 \: p \: - 10 - 3 + 4 - 4 p = 0

⇒- 9p = + 9

∴ p = -1


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