1.

The point of intersection of the tangents of the parabola `y^(2)=4x` drawn at the end point of the chord x+y=2 lies onA. x-2y=0B. x+2y=0C. y-x=0D. x+y=0

Answer» Correct Answer - C
(3) Let the point of intersection be `(alpha,beta)`.
Therefore, the chord of contact w.r.t. this point is
`betay=2x+aalpha`
which is the same as x+y=2. Therefore,
`alpha=beta=-2`
These value satisfy y-x=0.


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