Saved Bookmarks
| 1. |
The point of intersection of the tangents at the ends of the latusrectum of the parabola `y^2=4x`is_____________ |
|
Answer» Correct Answer - (-1,0) The coordinates of extremities of the latusrectum of `y^(2) = 4x` are (1,2) and (1,-2) Equation of tangents at these points are `y. 2 = (4(x + 1))/(2) implies 2y = 2 (x + 1)` and `y (-2) = (4(x + 1))/(2)` `implies -2y = 2 (x + 1)` `:. -2 (x + 1) = 2 (x + 1)` `implies 0 = 4 (x + 1)` `implies - 1 = x implies y = 0` Therefore, the required point is (-1,0) |
|