1.

the plane polarised electromagnetic wave is travelling in free space along +x direction. the amplitude of the electric field is E0= 240 N/c and its frequency is 150 Mhz. the electric field of the wave can be written as

Answer»

Electric FIELD of the wave ALONG positive X direction can be written as
\boxed{\bf{E=E_0sin(kx-\omega t)}}

so, first of all, we have to FIND out k, \omega

given, frequency of wave , f = 150MHz
= 150 × 10^6 Hz = 1.5 × 10^8 Hz
so, angular frequency , \omega = 2π × 150 × 10^6
= π × (300) × 10^6 rad/sec
= 3π × 10^8 rad/sec

K = \frac{\omega}{c}
c is the speed of light
so, K = 3π × 10^8/3 × 10^8 = π

now, equation of electric field of the wave is
E = 240sin(π x - 3π × 10^8) N/C


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