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the plain transmission grating has 6000 slits/cm find the angular separation between first and third order of the spectrum for a wavelength of 50 nm |
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Answer» Solution We know that the FIRST MAXIMUM (NEXT to central maximum) occurs at y=λDd Giventλˆ1=480nm λ2=600nm D=150cm=1.5mandd=0.25mm=0.25xx10^-3mso,y_1=(Dlamda_1)/d=((1.5)xx480xx10^-9)/(0.25xx10^-3)=2.88mmy_2=((1.5)xx600xx10^-9)/(0.25xx10^-3)sotheseparationbetweenthesetwobright∈≥sisgivenby:. SEPARATION =y2−y1 `=3.60-2.88=0.72mm. |
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