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The pitch of a screw gauge is `1mm` and its cap is divided into `100` divisions. When this screw gauge is used to measure the diameter of a wire, then main scale reading is `2 mm` and `58^(th)` division of circular scale coincides with the main scale. There is no zero error in the screw gage. Then the diameter of the wire isA. `2.38 mm`B. `2.48 mm`C. `2.58 mm`D. `3.58 mm` |
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Answer» Correct Answer - C the pitch of the screw gauge, `P = 1 mm` Lesat count, `L.C. = (P)/(N) = (1 mm)/(100) = 0.01mm` `:.` Diameter of the wire, `d = 2mm + 58 xx L.C.` `= 2mm + 58 xx 0.01 mm` `= 2.58mm` |
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