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The pitch of a screw gauge is `1` mm and there are `100` division on its circular scale. When nothing is put in between its jaws, the zero of the circular scale lies `4` divisions below the reference line. When a steel wire is placed between the jaws, two main scale divisions are clearly visible and `67` divisions on the circular scale are observed. the diameter of the wire isA. `2.71mm`B. `2.67mm`C. `2.63mm`D. `2.65mm` |
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Answer» Correct Answer - C `p=1mm,N=100` Least count `C=P/N=(1mm)/100=0.01mm` The instrument has a positive zero error `e=+NC=+4xx0.01=0.04mm` Main scale reading is `2xx(1mm)=2mm` Circular scale reading is `67(0.01)=0.67mm` `:.` observed reading is `R_(0)=2+0.67=2.67mm` So true reading `=R_(0)-e=2.63mm` |
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