The photograph of a house occupies an area of 1.75 cm2 on a 35 mm slid

1.	The photograph of a house occupies an area of 1.75 cm2 on a 35 mm slide. The slide is projected on to a screen and the area of the house on the screen is 1.55 m2. What is the linear magnification of the projector screen arrangement?
Answer» Given area of the house in photograph = 1.75 cm². Area of the house on screen = 1.55 m² = 1.55 x 10⁴ cm². Magnification in area of photograph = (1.55 x 10⁴/1.75) = 8.857 x 10³ cm² Linear magnification = √(areal magnification) = √(8.587 x 10³) = 94.1 cm².

The photograph of a house occupies an area of 1.75 cm2 on a 35 mm slide. The slide is projected on to a screen and the area of the house on the screen is 1.55 m2. What is the linear magnification of the projector screen arrangement?

Answer»

Given area of the house in photograph = 1.75 cm².

Area of the house on screen = 1.55 m² = 1.55 x 10⁴ cm².

Magnification in area of photograph

= (1.55 x 10⁴/1.75)

= 8.857 x 10³ cm²

Linear magnification

= √(areal magnification)

= √(8.587 x 10³)

= 94.1 cm².