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The photo-electron liberated from the surface of lithium (ϕ=2.39 eV) by electromagnetic radiation whose electric component varies with time as E=a(1+cosωt)cosω0t where a = constant, ω=6×1014 rad/s and ω0=3.60×1015rad/s, then the maximum kinetic energy of photo-electron is (in eV)

Answer» The photo-electron liberated from the surface of lithium (ϕ=2.39 eV) by electromagnetic radiation whose electric component varies with time as E=a(1+cosωt)cosω0t where a = constant, ω=6×1014 rad/s and

ω0=3.60×1015rad/s, then the maximum kinetic energy of photo-electron is (in eV)


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