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The phase trajectory in phase space of bullet of units mass fired straight upwards with initial speed of 392 m/s is |
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Answer» align="absmiddle" alt="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\orange{R }}}}}}}}}}}}}" class="latex-formula" id="TexFormula1" src="https://tex.z-dn.net/?F=%5Chuge%5Cbold%7B%5Cmathtt%7B%5Cpurple%7BA%7B%5Cpink%7B%20N%7B%5Cgreen%7BS%7B%5Cblue%7BW%7B%5Cred%7BE%7B%5Corange%7BR%20%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D" title="\huge\bold{\mathtt{\purple{A{\pink{ N{\green{S{\blue{W{\red{E{\orange{R }}}}}}}}}}}}}">... Given: Mass of Bullet = 10g Velocity of Bullet = 100 m/s Mass of gun = 500 g (0.5kg)
To Find: Momentum of Bullet? Velocity of Gun? Momentum of Gun?
Solution: ❖Momentum of Bullet; Mass of bullet is 10g => 1KG = 1000 g => kg = 10/1000 => kg = 0.01 kg Momentum = Mass ★ Momentum=Mass×Velocity Where p = Momentum m = Mass v = Velocity ➙ p = m × v ➙ p = 0.01 × 100 ➙ p = 1 kg.m/s Momentum of bullet is 1kg.m/s. ★ Momentum (Bullet)
=Momentum (Gun)
After substituting values, ➙ Momentum (bullet) = Momentum (Gun) ➙ m × v = m × v ➙ 0.01 × 100 = 0.5 × v ➙ 1/0.5 = v ➙ v = 2 m/s Velocity of Gun is 2 m/s.
❖Momentum of Gun; ★ Momentum=Mass×Velocity
➙ p = m × v ➙ p = 0.5 × 2 ➙ p = 1 kg.m/s Hence, The Momentum of gun is 1 kg.m/s. _____________________ Explanation: 100% CORRECT answer Hope it's helpful ✌️✌️
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