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The phase difference between the voltage and the current in an AC circuit is `pi//4`. If the frequency is `50Hz` then this phase difference will be equivalent to a time ofA. 0.05 sB. 2.5 millisecondC. 25 millisecondD. 0.25 s |
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Answer» Correct Answer - B Phase diff. = `(pi)/4 T = 1/n = 1/50 s` `:.` Time T correspond to a phase diff. of `2 pi` `:.` for a phase diff. of `(pi)/4`. `t = T/8 = 1/(50 xx 8) = 1/400 s :. t= 2.5` millisecond. |
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