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The pH of a solution is 5.5 at 25°C. Calculate its [OH-]. |
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Answer» pH = 5.5 Since pH + pOH = 14 pOH = 14 – pH = 14 – 5.5 = 8.5 [OH-] = 10-POH = 10-8.5 = 3.16 × 10-9 M (OR) [OH-] = antilog[-8.5] = 3.16 × 10-9 M [OH-] = 3.16 × 10-9 M |
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