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The pH of a solution formed by mixing 40 mL of 0.10 M HCl and 10 mL of 0.45 M NaOH is :(a) 5 (b) 8(c) 12 (d) 10 |
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Answer» Correct option: (c) 12 Explanation: Meq. of HCl = 40 x 0.1 = 4 Meq. of NaOH = 10 x 0.45 = 4.5 ∴ Meq. of NaOH left = 0.5 Now, [OH+] = 0.5/50 = 10-2 ∴ pOH = 2 and pH = 12 |
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