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The pH of a simple acetate buffer is given by `pH = pK_(a) + log.(["Salt"])/(["Acid"])` `K_(a)` of acetic acid `= 1.8 xx 10^(-5)` If [Salt] = [Acid] = 0.1 M, the pH of the solution would be aboutA. 7B. 4.7C. 5.3D. 1.4 |
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Answer» Correct Answer - B `["Salt"] = 0.1 M, ["Acid"] = 0.1 M` `K_(a) = 1.8 xx 10^(-5) , pH = -logK_(a) + log.(["Salt"])/(["Acid"])` `= -log 1.8 xx 10^(-5) + log.(0.1)/(0.1) = -log 1.8 xx 10^(-5)` `pH = 4.7`. |
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