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The pH of a dibasic acid is 3.699. Its molarityis1) 2 x 104M3) 2 x 10-3 M32*10-3M21 x 10-4MA 1x 104 M |
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Answer» Normality EQUAL to 10 to the power of -3.699 so molarity equal to 10 to the power of -3.699 DIVIDED by 2(dibasic acid) |
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