1.

The periodic time of simple pendulum is T = 2π√(ℓ/g) relative error in the measurement of T and ℓ are ±a and ±b respectively find relative error in the measurement of g(a) a + b       (b) 2b + a     (c) 2a + b      (d) a – b

Answer»

(c) 2a + b

Explanation:

T = 2π √(ℓ/g)

 ∴        T2 = (2π)2(ℓ/g)

  ∴        g = [(4π2ℓ) / (T2)]

(Δg / g) = (Δℓ / ℓ) + 2 (ΔT / T)

    = b + 2a 



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