1.

The period of oscillation of a simple pendulum is T in a stationary lift. If the lift moves upwards with an acceleration of 8g, the period will………….

Answer»

remain the same
decrease by T/2
increase by T/3
NONE of these

Solution :`T=2pisqrt((l)/(g)),T.=2pisqrt((l)/(g+8g))=(1)/(3)(2pisqrt((l)/(g)))=(T)/(3)`
THUS, the NEW TIME period is `T//3`.


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