1.

The perimeters of two squares are 60 metres and 144 metres respectively. Find theperimeter of another square equal in area to the sum of the first two squares.​

Answer»

Answer:

51

Step-by-step explanation:

the FIRST SQUARE PERIMETER is=60÷4=15

the second square perimeter=144÷4=36

so, the LAST square perimeter=36+15=51



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