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The perimeters of two squares are 60 metres and 144 metres respectively. Find theperimeter of another square equal in area to the sum of the first two squares. |
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Answer» Answer: 51 Step-by-step explanation: the FIRST SQUARE PERIMETER is=60÷4=15 the second square perimeter=144÷4=36 so, the LAST square perimeter=36+15=51 |
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