The perimeters of two squares are 40 cm and 32 cm. Find the perimeter

1.	The perimeters of two squares are 40 cm and 32 cm. Find the perimeter of third square wharea is equal to the difference of the areas of the two squares.
Answer» $\red{\textbf{Answer :- 24 cm}}$ $\textsf{We know perimeter of square = 4(side)}$ $\LARGE\textsf{So,}$ $\textsf{side of first square =40/4}$ $\textsf{=10cm}$ $\textsf{side of second square =32/4}$ $\textsf{= 8cm}$ $\Large\textsf{Area of third square =}$ $\textsf{1010-88}$ $\textsf{= 36cm}$ $\textsf{So side of third square =}$ $\textsf{6[because area of square = sideside].}$ $\Large\textsf{perimeter = 4 side}$ $\textsf{= 4*6 }$ $\textsf{= 24cm }$ $\red{\textbf{so, perimeter of third square = 24cm}}$