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The perimeter of the quadrant of a circle is 37.5 cm. Find the circle (in `cm^(2)`).A. 346.5B. 325.5C. 275.25D. 173.25 |
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Answer» Correct Answer - A Given that the perimeter of the quadrant of a circle is 37.5 cm. `rArr (2pi//4)+2r=37.5` `rArr(11r//7)+2r=37.5` `rArr(11//7+2)r=37.5` `rArr(25//7)r=37.5` `rArrr = 10.5` The area of the circle (in `cm^(2)`) = `pir^(2)` `=(22//7)(10.5)2` `=(22)(1.5)(10.5)` `=(33)(10.5)` `=(33)(10.5)` `=346.5` Hence, the correct option is (a). |
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