The perimeter of a triangular field is 540 m and its sides are in the – InterviewSolution

1.	The perimeter of a triangular field is 540 m and its sides are in the ratio `25: 17:12`. Find the area of the triangle. Also, find the cost ploughing the field at `Rs. 18.80` per `10 m^2`
Answer» perimeter =540m 25x+17x+12x=540m 54x=540m x=10m sides of triangle are 25x=250m 17x=170m 12x=120m S=250+170+120/2=270 area of triangle=`sqrt(s(s-a)(s-b)(s-c))` `=sqrt(270(270-250)(270-170)(270-120))` =9000`m^2` cost 10`m^2`=18.80Rs 1`m^2`=1.880Rs 9000`m^2`=9000*1.880=16920Rs.

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