the perimeter of a triangle measures 49 cm . one side is 7 cm longer t

1.	the perimeter of a triangle measures 49 cm . one side is 7 cm longer than the other and 5 cm shorter than the third. find the length of each side of the triangle
Answer» Answer : • Sides of ∆ are 10 cm , 17 cm and 22 cm ___________________________ Given : • Perimeter of ∆ = 49 cm • One side is longer by 7 cm • Other side is shorter by 5 cm To Find : • Each side of triangle Solution : • Let the side of ∆ be x • According to the question : → x + x - 7 + x + 5 = 49 → 3X - 2 = 49 → 3x = 49 + 2 → 3x = 51 → x = 51/3 → x = 17 • First side of ∆ = 17 cm • Second side of ∆ = x - 7 = 17 - 7 = 10 cm • Third side of ∆ = x + 5 = 17 + 5 = 22 cm _____________________

the perimeter of a triangle measures 49 cm . one side is 7 cm longer than the other and 5 cm shorter than the third. find the length of each side of the triangle

Answer»

Answer :

• Sides of ∆ are 10 cm , 17 cm and 22 cm

___________________________

Given :

• Perimeter of ∆ = 49 cm

• One side is longer by 7 cm

• Other side is shorter by 5 cm

To Find :

• Each side of triangle

Solution :

• Let the side of ∆ be x

• According to the question :

→ x + x - 7 + x + 5 = 49

→ 3X - 2 = 49

→ 3x = 49 + 2

→ 3x = 51

→ x = 51/3

→ x = 17

• First side of ∆ = 17 cm

• Second side of ∆ = x - 7 = 17 - 7 = 10 cm

• Third side of ∆ = x + 5 = 17 + 5 = 22 cm

_____________________

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the perimeter of a triangle measures 49 cm . one side is 7 cm longer than the other and 5 cm shorter than the third. find the length of each side of the triangle​