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The perimeter of a triangle is 8 + 13a + 7aand two of its sides are 2a2 + 3a + 2 and 3a²-4a-1, then the third side of the triangle is |
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Answer» Let X , Y, Z are three sides of triangle & P be the perimeter of triangle where X=2a^2+3a+2Y=3a^2-4a-1 Z=?P=7a^2+13a+8Now P= X+Y+Z7a^2+13a+8=2a^2+3a+2+3a^2-4a-1 +Z7a^2+13a+8=5a^2-a+1+1Z=7a^2-5a^2+13a+a+8-1Z=2a^2+14a+7Hence , the third side of triangle =2a^2+14a+7. |
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